Core Aeration Calculator
Enter the lawn area, the aerator's hole spacing, the core diameter and depth, and the number of passes. The calculator counts the holes, the percent of the surface they open and the volume of soil in the cores, which is also the topdressing it would take to fill them.
Holes per square foot
32
Holes in the lawn
160,000 holes
Surface opened
4.363%
Soil in one core
0.589 cu in
Soil removed
54.54 cu ft
Soil removed in cubic yards
2.0201 cu yd
Topdressing to refill the holes
54.54 cu ft
Soil removed as a layer over the lawn
0.1309 in
How it works
A core aerator pulls plugs of soil and thatch out of the lawn, leaving a grid of holes. On a grid with holes a inches apart across the machine and b inches apart along its travel, each hole has a × b square inches to itself, so one pass makes 144 ÷ (a × b) holes per square foot; more passes multiply that.
Each hole is a cylinder: its opening is π × (diameter ÷ 2)², and the soil it held is that area times the depth. Holes per square foot times the opening area, over 144 sq in, is the share of the surface opened. Holes times the core volume is the soil brought up, and the same volume of topdressing would fill the holes level.
Extension figures for the machine settings vary. Clemson HGIC 1200 (revised 2020) gives tines of 1/4 to 3/4 in, 2 to 3 in deep and 2 to 3 in apart, with two passes at right angles; Wisconsin A3710 notes piston aerators usually pull 3 in cores and drum units rarely more than 2 in.
Formula
holes per sq ft = 144 ÷ (spacing across × spacing along) × passes hole opening = π × (diameter ÷ 2)² (sq in) core volume = hole opening × depth (cu in) surface opened = holes per sq ft × hole opening ÷ 144 soil removed = holes per sq ft × area × core volume ÷ 1,728 (cu ft) topdressing to refill = soil removed
Example
Holes 3 in apart each way make 144 ÷ 9 = 16 holes per square foot per pass; two passes make 32. Over 5,000 sq ft that is 160,000 holes.
A 1/2 in core opens π × 0.25² = 0.196 sq in, so 32 holes open 6.28 sq in of every 144: 4.36% of the surface. At 3 in deep each core holds 0.589 cu in, and the lawn gives up 160,000 × 0.589 = 94,248 cu in, or 54.54 cu ft (2.02 cu yd). Spread over the lawn, that is a layer 0.131 in deep, and the same 54.54 cu ft of topdressing would refill the holes.
Assumptions and limitations
- Holes are taken as clean cylinders of the full diameter and depth, on an even grid. Tines that do not reach full depth in dry or hard soil, or spoon tines that make elongated holes, change the figures; Wisconsin A3710 notes drum units rarely go deeper than 2 in in dry soil.
- Holes from different passes are assumed not to overlap. Where they do, the surface opened and the soil removed are less than shown, so the figures are upper bounds.
- The default spacing, core size, depth and passes are illustrative values within the extension ranges cited above, not settings for a particular machine; the spacing for a given aerator is in its manual.
- Cores contain thatch and roots as well as soil, so the topdressing figure is the volume of the holes, not the weight of soil to buy. Wisconsin A3710 describes topdressing as a thin layer, usually no more than 1/4 to 1/2 in.
Frequently asked questions
Why does the surface opened look so small?
A 1/2 in hole is about 0.2 sq in. Even 32 of them in a square foot open only 6.3 of its 144 sq in, a little over 4%. Closer spacing, wider tines or more passes raise it; halving the spacing in both directions quadruples the number of holes.
How much thatch does one aeration remove?
Colorado State University Extension (Fact Sheet 7.202) states that a single aeration with 1/2 in tines removes about 10 percent of the thatch when enough passes are made to average 2 in between holes. That figure is for thatch, not surface area: the geometry here gives 4.9% of the surface for 1/2 in holes on a 2 in grid.
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