Annulus (Ring) Area Calculator
Enter the outer and inner radii, or the outer and inner diameters, to get the ring area, its width and both circumferences.
Ring area
50.2655 ft²
Ring width
2 ft
Outer radius
5 ft
Inner radius
3 ft
Outer circumference
31.4159 ft
Inner circumference
18.8496 ft
Outer circle area
78.5398 ft²
Inner circle area
28.2743 ft²
How it works
An annulus is the flat ring left when a smaller circle is cut out of the centre of a larger one: a washer, the end of a pipe, the wall of a round planter, a path around a circular lawn. Its area is simply the big circle's area minus the small circle's area, πR² − πr², which factors to π(R − r)(R + r): the ring width times the mean circumference, π(R + r).
Give the two radii (centre to edge) or the two diameters (edge to edge through the centre); diameters are what calipers and pipe tables give, and the calculator halves them. The ring width is the difference of the radii, which for a pipe is the wall thickness. Both circumferences come from 2πr.
The unit box does not convert anything. It records the unit you measured in so the results are labelled correctly: lengths in that unit, areas in that unit squared.
Formula
R = D ÷ 2, r = d ÷ 2 (when diameters are given) area = π(R² − r²) = π(R − r)(R + r) width = R − r outer circumference = 2πR inner circumference = 2πr
Example
A ring with an outer radius of 5 ft and an inner radius of 3 ft has an area of π(25 − 9) = 16π ≈ 50.27 ft². The ring is 2 ft wide, and the circumferences are 2π × 5 ≈ 31.42 ft outside and 2π × 3 ≈ 18.85 ft inside.
A 2-inch Schedule 40 steel pipe has an outside diameter of 2.375 in and an inside diameter of 2.067 in. Switching to diameters and inches, the wall cross-section is π(1.1875² − 1.0335²) ≈ 1.0745 in² and the wall is 0.154 in thick, matching the 1.075 sq in metal area in published pipe tables.
Assumptions and limitations
- The two circles share the same centre. An off-centre bore has the same area but an uneven wall.
- All lengths are in the unit you chose. The calculator labels the results with it and does not convert between units.
- The result is a flat area. Multiply it by a length to get the volume of a pipe wall or a tube.
- Results are rounded for display only.
Frequently asked questions
Can the inner radius be zero?
Yes. With no hole the ring is a full disc and the area is πR². Equal radii are also accepted and give a zero-width ring with zero area.
How do I get the weight of a pipe from this?
Multiply the wall cross-section area by the pipe length to get the volume of metal, then by the material's density. For steel at about 0.2836 lb per cubic inch, the 2-inch Schedule 40 example above weighs 1.0745 × 12 × 0.2836 ≈ 3.66 lb per foot, within rounding of the 3.65 lb/ft that pipe tables list.
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